I needed to review the Nyquist–Shannon sampling theorem. The coolest thing about Nyquist is that it expresses the sample-rate in terms of the function’s bandwidth and leads to a formula for the mathematically ideal interpolation algorithm.

### What is sampling?

Sampling is nothing more than converting a signal into a numeric sequence. Shannon states:

If a function x(t) contains no frequencies higher than B hertz, it is completely determined by giving its ordinates at a series of points spaced 1/(2B) seconds apart.

This is really simple: A sufficient sample-rate is therefore samples/second, or anything larger. The two thresholds, and , are respectively called the Nyquist rate and Nyquist frequency.

I can’t understand something unless I explore with it. So, I defined the following code.

First we have to make the following definitions for a given sample-rate of :

- $$ \scriptstyle T \stackrel{\mathrm{def}}{=}\ 1/f_s $$ represents the interval between samples.

Say we have a simple sign wave modulated at a frequency of 1/8.

If we explore, we can get:

### Aliasing

When the bandlimit is too high (or there is no bandlimit), the reconstruction exhibits imperfections known as aliasing.

Let be the Fourier transform of bandlimited function :

$$ X(f) \stackrel{\mathrm{def}}{=}\ \int_{-\infty}^{\infty} x(t) \ e^{- i 2 \pi f t} \ {\rm d}t $$

and

$$ X(f) = 0 \quad \text{for all} |f| > B $$

The Poisson summation formula shows that the samples, x(nT), of function x(t) are sufficient to create a periodic summation of function X(f). The result is:

$$ X_s(f)\ \stackrel{\mathrm{def}}{=} \sum_{k=-\infty}^{\infty} X\left(f – k f_s\right) = \sum_{n=-\infty}^{\infty} \underbrace{T\cdot x(nT)}_{x[n]}\ e^{-i 2\pi n T f}, $$

This function is also known as the discrete-time Fourier transform.

Questions I’m after:

- How is it that the samples of several different sine waves can be identical, when at least one of them is at a frequency above half the sample rate?

You can see my source code here:

Looks impressive, my son. Love from your proud Mom! 🙂